3.2153 \(\int \frac{(3+5 x)^2}{(1-2 x)^{5/2} (2+3 x)^2} \, dx\)

Optimal. Leaf size=81 \[ -\frac{130}{1029 \sqrt{1-2 x}}-\frac{365}{294 \sqrt{1-2 x} (3 x+2)}+\frac{121}{42 (1-2 x)^{3/2} (3 x+2)}+\frac{130 \tanh ^{-1}\left (\sqrt{\frac{3}{7}} \sqrt{1-2 x}\right )}{343 \sqrt{21}} \]

[Out]

-130/(1029*Sqrt[1 - 2*x]) + 121/(42*(1 - 2*x)^(3/2)*(2 + 3*x)) - 365/(294*Sqrt[1 - 2*x]*(2 + 3*x)) + (130*ArcT
anh[Sqrt[3/7]*Sqrt[1 - 2*x]])/(343*Sqrt[21])

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Rubi [A]  time = 0.0217992, antiderivative size = 81, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 5, integrand size = 24, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.208, Rules used = {89, 78, 51, 63, 206} \[ -\frac{130}{1029 \sqrt{1-2 x}}-\frac{365}{294 \sqrt{1-2 x} (3 x+2)}+\frac{121}{42 (1-2 x)^{3/2} (3 x+2)}+\frac{130 \tanh ^{-1}\left (\sqrt{\frac{3}{7}} \sqrt{1-2 x}\right )}{343 \sqrt{21}} \]

Antiderivative was successfully verified.

[In]

Int[(3 + 5*x)^2/((1 - 2*x)^(5/2)*(2 + 3*x)^2),x]

[Out]

-130/(1029*Sqrt[1 - 2*x]) + 121/(42*(1 - 2*x)^(3/2)*(2 + 3*x)) - 365/(294*Sqrt[1 - 2*x]*(2 + 3*x)) + (130*ArcT
anh[Sqrt[3/7]*Sqrt[1 - 2*x]])/(343*Sqrt[21])

Rule 89

Int[((a_.) + (b_.)*(x_))^2*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Simp[((b*c - a*
d)^2*(c + d*x)^(n + 1)*(e + f*x)^(p + 1))/(d^2*(d*e - c*f)*(n + 1)), x] - Dist[1/(d^2*(d*e - c*f)*(n + 1)), In
t[(c + d*x)^(n + 1)*(e + f*x)^p*Simp[a^2*d^2*f*(n + p + 2) + b^2*c*(d*e*(n + 1) + c*f*(p + 1)) - 2*a*b*d*(d*e*
(n + 1) + c*f*(p + 1)) - b^2*d*(d*e - c*f)*(n + 1)*x, x], x], x] /; FreeQ[{a, b, c, d, e, f, n, p}, x] && (LtQ
[n, -1] || (EqQ[n + p + 3, 0] && NeQ[n, -1] && (SumSimplerQ[n, 1] ||  !SumSimplerQ[p, 1])))

Rule 78

Int[((a_.) + (b_.)*(x_))*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> -Simp[((b*e - a*f
)*(c + d*x)^(n + 1)*(e + f*x)^(p + 1))/(f*(p + 1)*(c*f - d*e)), x] - Dist[(a*d*f*(n + p + 2) - b*(d*e*(n + 1)
+ c*f*(p + 1)))/(f*(p + 1)*(c*f - d*e)), Int[(c + d*x)^n*(e + f*x)^(p + 1), x], x] /; FreeQ[{a, b, c, d, e, f,
n}, x] && LtQ[p, -1] && ( !LtQ[n, -1] || IntegerQ[p] ||  !(IntegerQ[n] ||  !(EqQ[e, 0] ||  !(EqQ[c, 0] || LtQ
[p, n]))))

Rule 51

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[((a + b*x)^(m + 1)*(c + d*x)^(n + 1
))/((b*c - a*d)*(m + 1)), x] - Dist[(d*(m + n + 2))/((b*c - a*d)*(m + 1)), Int[(a + b*x)^(m + 1)*(c + d*x)^n,
x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && LtQ[m, -1] &&  !(LtQ[n, -1] && (EqQ[a, 0] || (NeQ[
c, 0] && LtQ[m - n, 0] && IntegerQ[n]))) && IntLinearQ[a, b, c, d, m, n, x]

Rule 63

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[{p = Denominator[m]}, Dist[p/b, Sub
st[Int[x^(p*(m + 1) - 1)*(c - (a*d)/b + (d*x^p)/b)^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] &
& NeQ[b*c - a*d, 0] && LtQ[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntLinearQ[a,
b, c, d, m, n, x]

Rule 206

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1*ArcTanh[(Rt[-b, 2]*x)/Rt[a, 2]])/(Rt[a, 2]*Rt[-b, 2]), x]
/; FreeQ[{a, b}, x] && NegQ[a/b] && (GtQ[a, 0] || LtQ[b, 0])

Rubi steps

\begin{align*} \int \frac{(3+5 x)^2}{(1-2 x)^{5/2} (2+3 x)^2} \, dx &=\frac{121}{42 (1-2 x)^{3/2} (2+3 x)}-\frac{1}{42} \int \frac{-15+525 x}{(1-2 x)^{3/2} (2+3 x)^2} \, dx\\ &=\frac{121}{42 (1-2 x)^{3/2} (2+3 x)}-\frac{365}{294 \sqrt{1-2 x} (2+3 x)}-\frac{65}{147} \int \frac{1}{(1-2 x)^{3/2} (2+3 x)} \, dx\\ &=-\frac{130}{1029 \sqrt{1-2 x}}+\frac{121}{42 (1-2 x)^{3/2} (2+3 x)}-\frac{365}{294 \sqrt{1-2 x} (2+3 x)}-\frac{65}{343} \int \frac{1}{\sqrt{1-2 x} (2+3 x)} \, dx\\ &=-\frac{130}{1029 \sqrt{1-2 x}}+\frac{121}{42 (1-2 x)^{3/2} (2+3 x)}-\frac{365}{294 \sqrt{1-2 x} (2+3 x)}+\frac{65}{343} \operatorname{Subst}\left (\int \frac{1}{\frac{7}{2}-\frac{3 x^2}{2}} \, dx,x,\sqrt{1-2 x}\right )\\ &=-\frac{130}{1029 \sqrt{1-2 x}}+\frac{121}{42 (1-2 x)^{3/2} (2+3 x)}-\frac{365}{294 \sqrt{1-2 x} (2+3 x)}+\frac{130 \tanh ^{-1}\left (\sqrt{\frac{3}{7}} \sqrt{1-2 x}\right )}{343 \sqrt{21}}\\ \end{align*}

Mathematica [C]  time = 0.0167756, size = 55, normalized size = 0.68 \[ -\frac{-130 \left (6 x^2+x-2\right ) \, _2F_1\left (-\frac{1}{2},1;\frac{1}{2};\frac{3}{7}-\frac{6 x}{7}\right )-7 (365 x+241)}{1029 (1-2 x)^{3/2} (3 x+2)} \]

Antiderivative was successfully verified.

[In]

Integrate[(3 + 5*x)^2/((1 - 2*x)^(5/2)*(2 + 3*x)^2),x]

[Out]

-(-7*(241 + 365*x) - 130*(-2 + x + 6*x^2)*Hypergeometric2F1[-1/2, 1, 1/2, 3/7 - (6*x)/7])/(1029*(1 - 2*x)^(3/2
)*(2 + 3*x))

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Maple [A]  time = 0.011, size = 54, normalized size = 0.7 \begin{align*}{\frac{2}{1029}\sqrt{1-2\,x} \left ( -2\,x-{\frac{4}{3}} \right ) ^{-1}}+{\frac{130\,\sqrt{21}}{7203}{\it Artanh} \left ({\frac{\sqrt{21}}{7}\sqrt{1-2\,x}} \right ) }+{\frac{121}{147} \left ( 1-2\,x \right ) ^{-{\frac{3}{2}}}}-{\frac{44}{343}{\frac{1}{\sqrt{1-2\,x}}}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((3+5*x)^2/(1-2*x)^(5/2)/(2+3*x)^2,x)

[Out]

2/1029*(1-2*x)^(1/2)/(-2*x-4/3)+130/7203*arctanh(1/7*21^(1/2)*(1-2*x)^(1/2))*21^(1/2)+121/147/(1-2*x)^(3/2)-44
/343/(1-2*x)^(1/2)

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Maxima [A]  time = 3.62382, size = 100, normalized size = 1.23 \begin{align*} -\frac{65}{7203} \, \sqrt{21} \log \left (-\frac{\sqrt{21} - 3 \, \sqrt{-2 \, x + 1}}{\sqrt{21} + 3 \, \sqrt{-2 \, x + 1}}\right ) - \frac{2 \,{\left (195 \,{\left (2 \, x - 1\right )}^{2} + 3465 \, x + 1232\right )}}{1029 \,{\left (3 \,{\left (-2 \, x + 1\right )}^{\frac{5}{2}} - 7 \,{\left (-2 \, x + 1\right )}^{\frac{3}{2}}\right )}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((3+5*x)^2/(1-2*x)^(5/2)/(2+3*x)^2,x, algorithm="maxima")

[Out]

-65/7203*sqrt(21)*log(-(sqrt(21) - 3*sqrt(-2*x + 1))/(sqrt(21) + 3*sqrt(-2*x + 1))) - 2/1029*(195*(2*x - 1)^2
+ 3465*x + 1232)/(3*(-2*x + 1)^(5/2) - 7*(-2*x + 1)^(3/2))

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Fricas [A]  time = 1.65208, size = 232, normalized size = 2.86 \begin{align*} \frac{65 \, \sqrt{21}{\left (12 \, x^{3} - 4 \, x^{2} - 5 \, x + 2\right )} \log \left (\frac{3 \, x - \sqrt{21} \sqrt{-2 \, x + 1} - 5}{3 \, x + 2}\right ) + 7 \,{\left (780 \, x^{2} + 2685 \, x + 1427\right )} \sqrt{-2 \, x + 1}}{7203 \,{\left (12 \, x^{3} - 4 \, x^{2} - 5 \, x + 2\right )}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((3+5*x)^2/(1-2*x)^(5/2)/(2+3*x)^2,x, algorithm="fricas")

[Out]

1/7203*(65*sqrt(21)*(12*x^3 - 4*x^2 - 5*x + 2)*log((3*x - sqrt(21)*sqrt(-2*x + 1) - 5)/(3*x + 2)) + 7*(780*x^2
+ 2685*x + 1427)*sqrt(-2*x + 1))/(12*x^3 - 4*x^2 - 5*x + 2)

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Sympy [F(-2)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((3+5*x)**2/(1-2*x)**(5/2)/(2+3*x)**2,x)

[Out]

Exception raised: ValueError

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Giac [A]  time = 2.17235, size = 104, normalized size = 1.28 \begin{align*} -\frac{65}{7203} \, \sqrt{21} \log \left (\frac{{\left | -2 \, \sqrt{21} + 6 \, \sqrt{-2 \, x + 1} \right |}}{2 \,{\left (\sqrt{21} + 3 \, \sqrt{-2 \, x + 1}\right )}}\right ) - \frac{11 \,{\left (24 \, x + 65\right )}}{1029 \,{\left (2 \, x - 1\right )} \sqrt{-2 \, x + 1}} - \frac{\sqrt{-2 \, x + 1}}{343 \,{\left (3 \, x + 2\right )}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((3+5*x)^2/(1-2*x)^(5/2)/(2+3*x)^2,x, algorithm="giac")

[Out]

-65/7203*sqrt(21)*log(1/2*abs(-2*sqrt(21) + 6*sqrt(-2*x + 1))/(sqrt(21) + 3*sqrt(-2*x + 1))) - 11/1029*(24*x +
65)/((2*x - 1)*sqrt(-2*x + 1)) - 1/343*sqrt(-2*x + 1)/(3*x + 2)